Anhydrous `AlCl_(3) ` is covalent, From the data given below, predict whether if would remain covelent or become ionic in aqueous sobittion [Inization energy for Al `=- 5137 kJ mol ^(-1), Delta H_("Hydration")` for `Al ^(3+) =- 4665 kJ mol ^(-1),` for ` Cl =-381 kJ mol ^(-1) ]`
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Total energy released `=1Delta_("hyd")H(Al^(3+))+3Delta_("hyd")H(Cl^(-))` `=[(-4665)+(3xx-381)]kJmol^(-1)=-5808kJmol^(-1)` Total energy required `=Delta_(i)H(AlCl_(3))=5137kJmol^(-1)` Since energy released is greater than the energy required, the compound will ionize in aqueous solution.
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Anhydrous AlCl_(3) is covalent. From the date given below, predict whether it would remain covalent or become ionic in aqueous solution. (Ionisation energy for Al is 1537 kJ mol^(-1) ) Delta_("hydration") for Al^(3+) = - 4665 kJ mol^(-1) Delta_("hydration") for Cl^(Ө) = - 381 kJ mol^-1 .
Ionisation energy of A1=5137KJmol^(-1)(DeltaH) hydration of Al^(3+)=-4665KJmol^(-1).(DeltaH)_(hydration) for Cl^(-)=-381KJmol^(-1) . Which of the following statement is correct?
CBSE COMPLEMENTARY MATERIAL-CHEMICAL BONDING AND MOLECULAR STRUCTURE -HOTS QUESTIONS
