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Calculate the enthalpy change for the re...

Calculate the enthalpy change for the reaction `H_(2)(g) + Br_(2)rarr 2HBr (g)` Give that the bond enthalpies ofH-H,Br-Br and H-Br are435, 192 and 364kJ `mol^(-1)` respectively.

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`-109 kJ mol^(-1)`
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Use the bond enthalpies listed below to estimate the enthalpy change for the reaction H_(2)(g)+Br_(2)(g)rarr2HBr(g) Given: BE of H_(2), Br_(2) , and HBr is 435, 192 , and 368 kJ mol^(-1) , respectively.

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The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :

At standard conditions, if the change in the enthalpy for the following reaction is -109KJ mol^(-1) H_2(g) + Br_2(g) rarr 2HBr(g) Given that bond energy of H_2 and Br_2 is 435kj mol^(-1) and 192kj mol^(-1) , respectively. What is the bond energy of HBr ?

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