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The reaction of cyanamide, NH(2)CN(s), w...

The reaction of cyanamide, `NH_(2)CN(s)`, with Dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `-742.7 kJ mol^(-1)` at 298K. Calculate Enthalpy change for the reaction at 298K,
`NH_(2) CN (s) + 3//2O_(2)(g) rarr N_(2)(g) + CO_(2) (g) + H_(2)O(I)`

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To calculate the enthalpy change (ΔH) for the reaction of cyanamide (NH₂CN) with dioxygen (O₂), we can use the relationship between internal energy change (ΔU) and enthalpy change (ΔH). The formula we will use is: \[ \Delta H = \Delta U + \Delta N_G RT \] Where: - ΔU is the change in internal energy (given as -742.7 kJ/mol), ...
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