Write True/False:
`O_(2)^(+)` has oxidation state of oxygen as `+1//2`.

Answer

To determine whether the statement "O₂⁺ has an oxidation state of oxygen as +1/2" is true or false, we can follow these steps:

### Step 1: Understand the concept of oxidation state
The oxidation state of an element in a compound or ion is a measure of the degree of oxidation (loss of electrons) of that element. For a neutral molecule, the sum of the oxidation states of all atoms must equal zero. For an ion, the sum of the oxidation states must equal the charge of the ion.

### Step 2: Identify the species
In this case, we are looking at the ion O₂⁺. This indicates that we have two oxygen atoms and an overall charge of +1.

### Step 3: Set up the equation
Let the oxidation state of each oxygen atom be represented as X. Since there are two oxygen atoms in O₂⁺, we can express the total oxidation state as:
\[ 2X = \text{Overall charge} \]
Given that the overall charge of O₂⁺ is +1, we can write:
\[ 2X = +1 \]

### Step 4: Solve for X
To find the oxidation state X, we can rearrange the equation:
\[ X = \frac{+1}{2} \]
Thus, the oxidation state of each oxygen atom in O₂⁺ is +1/2.

### Step 5: Conclusion
Since we have calculated that the oxidation state of oxygen in O₂⁺ is indeed +1/2, we can conclude that the statement "O₂⁺ has an oxidation state of oxygen as +1/2" is **True**.

### Final Answer
**True**

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