What is the oxidation state of Oxygen in `H_(2)O_(2)`.

Answer

To find the oxidation state of oxygen in hydrogen peroxide (H₂O₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the formula and components**: The chemical formula for hydrogen peroxide is H₂O₂, which consists of two hydrogen (H) atoms and two oxygen (O) atoms.

2. **Assign oxidation states to known elements**:
- The oxidation state of hydrogen (H) is typically +1. Since there are two hydrogen atoms in H₂O₂, their total contribution to the oxidation state is:
\[ 2 \times (+1) = +2 \]

3. **Set up the equation for the overall charge**:
- The overall charge of a neutral compound like H₂O₂ is 0. Let’s denote the oxidation state of oxygen as \( x \). Since there are two oxygen atoms, their total contribution will be \( 2x \).
- The equation can be set up as follows:
\[ +2 + 2x = 0 \]

4. **Solve for the oxidation state of oxygen**:
- Rearranging the equation gives:
\[ 2x = -2 \]
- Dividing both sides by 2 results in:
\[ x = -1 \]

5. **Conclusion**:
- The oxidation state of oxygen in H₂O₂ is -1.

### Final Answer:
The oxidation state of oxygen in H₂O₂ is -1.

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