Benzene `underset("anhydrous" AICI_(3))overset(CH_(3)CI)(to) X overset("alkaline" KMnO_(4))(to) Y overset("alkaline" KMnO_(4))(to) Z`, The product Z is

Options

A. Benzaldehyde
B. Benzoicacid
C. Benzene
D. Toluene

Answer

To solve the problem step by step, we will analyze the reactions taking place in the given sequence.

### Step 1: Reaction of Benzene with CH₃Cl and AlCl₃
- **Reaction:** Benzene reacts with methyl chloride (CH₃Cl) in the presence of anhydrous aluminum chloride (AlCl₃).
- **Mechanism:** This is a Friedel-Crafts alkylation reaction. In this reaction, CH₃Cl acts as an electrophile after being activated by AlCl₃.
- **Product:** The methyl group (CH₃) attaches to the benzene ring, forming toluene (C₆H₅CH₃).
- **Result:** The product X is **toluene**.

### Step 2: Reaction of Toluene with Alkaline KMnO₄
- **Reaction:** Toluene (C₆H₅CH₃) is treated with alkaline potassium permanganate (KMnO₄).
- **Mechanism:** The KMnO₄ oxidizes the methyl group (CH₃) of toluene to a carboxylic acid group (COOH).
- **Product:** This oxidation leads to the formation of potassium benzoate (C₆H₅COOK).
- **Result:** The product Y is **potassium benzoate**.

### Step 3: Reaction of Potassium Benzoate with Alkaline KMnO₄
- **Reaction:** Potassium benzoate (C₆H₅COOK) is again treated with alkaline KMnO₄.
- **Mechanism:** The carboxylate ion (COOK) can be further oxidized to form benzoic acid (C₆H₅COOH).
- **Product:** The final product Z is **benzoic acid**.

### Summary of Products:
- **X (Toluene):** C₆H₅CH₃
- **Y (Potassium Benzoate):** C₆H₅COOK
- **Z (Benzoic Acid):** C₆H₅COOH

### Final Answer:
The product Z is **benzoic acid (C₆H₅COOH)**.

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