What happens when `CH_(3)CHO` is treated with `K_(2)Cr_(2)O_(7)` in presence of `H_(2)SO_4` ?

Explanation

To solve the question of what happens when acetaldehyde (CH₃CHO) is treated with potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is acetaldehyde (CH₃CHO).
- The oxidizing agent is potassium dichromate (K₂Cr₂O₇).
- The acidic medium is sulfuric acid (H₂SO₄).
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