An organic compound 'A' `(C_3H_6O)` is resistant to oxidation but forms compound 'B' `(C_3H_8O)` on reduction. 'B' reacts with HBr to form the compound 'C' .'C' with Mg forms Grignard's reagent 'D' which reacts with 'A' to form a product which on hydrolysis gives 'E'. Identify 'A' to 'E'.

Explanation

To solve the problem step-by-step, we will identify the compounds A to E based on the given information.

### Step 1: Identify Compound A
The molecular formula of compound A is \(C_3H_6O\). It is stated that A is resistant to oxidation, which suggests that it is likely a ketone. The only ketone with the formula \(C_3H_6O\) is **acetone** (or propan-2-one), which is \(CH_3COCH_3\).

**Hint:** Look for a compound that fits the molecular formula and is resistant to oxidation. Ketones are typically resistant to oxidation.

### Step 2: Identify Compound B
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