Home
Class 10
MATHS
Find the value of (-1)^(n)+(-1)^(2n)+(-1...

Find the value of `(-1)^(n)+(-1)^(2n)+(-1)^(2n_1)+(-1)^(4n+2)`, where n is any positive and integer.

Text Solution

Verified by Experts

The correct Answer is:
0
Promotional Banner

Topper's Solved these Questions

  • REAL NUMBERS

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER TYPE QUESTION-II|21 Videos

  • REAL NUMBERS

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTION|15 Videos

  • REAL NUMBERS

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTION|15 Videos

  • QUADRATIC EQUATIONS

    CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE TEST|10 Videos

  • SOME APPLICATIONS OF TRIGONOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE-TEST (SECTION-D)|1 Videos

Similar Questions

Explore conceptually related problems

Solve (x-1)^(n)=x^(n), where n is a positive integer.

((1+i)/(1-i))^(4n+1) where n is a positive integer.

Find the value of prod_(n-2)^(n) (1 - (1)/(n^(2)))

Show that the middle term in the expansion of (1+x)^(2n) is ((1.3.5...2n-1)))/(n!)2^(n)x^(n), where n is a positive integer.

The value of (n!)^(n) if n+(n-1)+(n-2)=n(n-1)(n-2) where n^(3)>9, a positive number is

Show that the middle term in the expansion of (1+x)^(2n) is (1.3.5...*(2n-1))/(n!)2nx^(n)2nx^(n) where n is a positive integer.

If the middle term in the expreansion of (1+x)^(2n) is ([1.3.5….(2n-1)])/(n!) (k) , where n is a positive integer , then k is .

The sum of the digits in (10^(2n^(2)+5n+1)+1)^(2) (where n is a positive integer),is