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If triangleABC ~ triangleFED," then "(AB...

If `triangleABC ~ triangleFED," then "(AB)/(-)=(-)/(ED)`.

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To solve the problem, we need to establish the relationship between the sides of the two similar triangles, triangle ABC and triangle FED. ### Step-by-Step Solution: 1. **Identify the Similar Triangles**: We know that triangle ABC is similar to triangle FED. This means that the corresponding sides of these triangles are in proportion. 2. **Write the Proportionality Statement**: Since the triangles are similar, we can write the following ratios based on their corresponding sides: \[ \frac{AB}{FE} = \frac{BC}{ED} = \frac{AC}{FD} \] 3. **Focus on the Required Ratio**: We need to express the ratio \( \frac{AB}{?} = \frac{BC}{ED} \). From the proportionality statement, we can see that: \[ \frac{AB}{FE} = \frac{BC}{ED} \] 4. **Substituting the Known Values**: From the proportionality, we can rearrange the equation to find the unknown: \[ \frac{AB}{FE} = \frac{BC}{ED} \] This means that if we cross-multiply, we get: \[ AB \cdot ED = BC \cdot FE \] 5. **Final Expression**: To express \( AB \) in terms of \( ED \) and \( FE \), we can write: \[ \frac{AB}{FE} = \frac{BC}{ED} \implies AB = \frac{BC \cdot FE}{ED} \] ### Conclusion: The final proportional relationship we derived is: \[ \frac{AB}{FE} = \frac{BC}{ED} \]
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CBSE COMPLEMENTARY MATERIAL-TRIANGLE-Short Answer Type Questions-II
  1. If triangleABC ~ triangleFED," then "(AB)/(-)=(-)/(ED).

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  2. In the given figure, (QR)/(QS)= (QT)/(PR) and angle1 = angle2 then pro...

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  3. In equilateral triangleABC, ADbotBC. Prove that 3BC^2= 4AD^2.

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  4. In the given figure angleABC=90^(@) and CD bot AB. Prove that (BC^(2)...

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  5. In Fig. 4.179, A B C and D B C are on the same base B C . If A...

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  6. If AD and PS are medians of triangleABC and trianglePQR respectively w...

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  7. In the given figure, DE || AC. Which of the following is correct? x=(...

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  8. Prove that the sum of the squares of the sides of a rhombus is equa...

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  9. A street light bulb is fixed on a pole 6 m above the level of the stre...

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  10. Two poles of height a metres and b metres are p metres apart. Prove th...

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  11. In the given figure AB || PQ || CD, AB=x, CD=y and PQ=z. Prove that 1/...

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  12. In the given figure (PS)/(SQ)=(PT)/(TR) and anglePST = anglePRQ. Prove...

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  13. In the figure, a point O inside triangleABC is joined to its vertices....

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  14. Two triangles B A Ca n dB D C , right angled at Aa n dD respectively, ...

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  15. The Hypotenuse of a right triangle is 25 cm and out of the remaining t...

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  16. In the given figure DE || AC and (BE)/(EC)=(BC)/(CP). Prove that DC |...

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  17. In a quadrilateral ABCD, angleB=90^(@) and AD^(2)= AB^(2) + BC^(2)+CD^...

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  18. In the given figure, DE || BC, DE= 3 cm, BC = 9 cm and ar (DADE) = 30c...

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  19. In an equilateral triangle ABC, D is a point on side BC such that B D=...

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  20. Ii DeltaPQR, PDbotQR such that D lies on QR, if PQ=a,PR=b,QD=c and DR=...

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  21. The ratio of the the areas of two similar triangles is equal to the ra...

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