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If `triangleABC ~ triangleDEF, ar(triangleDEF) =100cm^(2) and (AB)/(DE)=1/2," then ar(DABC) is"`

A

`50cm^(2)`

B

`25cm^(2)`

C

`4cm^(2)`

D

`200cm^(2)`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the relationship between the two triangles Given that triangle ABC is similar to triangle DEF, we know that the ratio of their areas is equal to the square of the ratio of their corresponding sides. ### Step 2: Write the formula for the ratio of areas The formula for the ratio of the areas of two similar triangles is: \[ \frac{ar(triangle ABC)}{ar(triangle DEF)} = \left(\frac{AB}{DE}\right)^2 \] ### Step 3: Substitute the known values We know: - \( ar(triangle DEF) = 100 \, cm^2 \) - \( \frac{AB}{DE} = \frac{1}{2} \) Substituting these values into the formula gives: \[ \frac{ar(triangle ABC)}{100} = \left(\frac{1}{2}\right)^2 \] ### Step 4: Calculate the square of the ratio of sides Calculating the square of \( \frac{1}{2} \): \[ \left(\frac{1}{2}\right)^2 = \frac{1}{4} \] ### Step 5: Set up the equation Now we can set up the equation: \[ \frac{ar(triangle ABC)}{100} = \frac{1}{4} \] ### Step 6: Solve for \( ar(triangle ABC) \) To find \( ar(triangle ABC) \), multiply both sides by 100: \[ ar(triangle ABC) = 100 \times \frac{1}{4} = 25 \, cm^2 \] ### Final Answer Thus, the area of triangle ABC is: \[ ar(triangle ABC) = 25 \, cm^2 \] ---
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