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A tower is 50 m high. When the sun's alt...

A tower is 50 m high. When the sun's altitude is `45^(@)` then what will be the length of its shadow ?

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To solve the problem of finding the length of the shadow of a tower that is 50 m high when the sun's altitude is 45°, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We have a tower that is 50 m tall, and we need to find the length of its shadow when the sun's altitude is 45°. 2. **Drawing a Diagram**: Draw a right triangle where: - The height of the tower (AB) is 50 m (perpendicular side). - The length of the shadow (BC) is what we need to find (base). - The angle of elevation from the tip of the shadow to the top of the tower (angle C) is 45°. 3. **Using Trigonometric Ratios**: We can use the tangent function, which relates the angle of elevation to the opposite side (height of the tower) and the adjacent side (length of the shadow). \[ \tan(C) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{AB}{BC} \] Here, \( AB = 50 \) m and \( BC = x \) (the length of the shadow). 4. **Substituting Known Values**: Since angle C is 45°, we have: \[ \tan(45°) = \frac{50}{x} \] 5. **Using the Value of Tan(45°)**: We know that: \[ \tan(45°) = 1 \] Therefore, we can write: \[ 1 = \frac{50}{x} \] 6. **Solving for x**: Rearranging the equation gives us: \[ x = 50 \] Thus, the length of the shadow is 50 m. ### Final Answer: The length of the shadow of the tower is **50 meters**. ---
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