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The angles of elevation and depression o...

The angles of elevation and depression of the top and bottom of a light house from the top of a building 60 m high are `30^(@)` and `60^(@)` respectively. Find
The difference between the height of the light house and the building.

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To solve the problem, we will follow these steps: ### Step 1: Understand the Problem We have a building of height 60 m and a lighthouse whose height we need to find. The angle of elevation to the top of the lighthouse from the top of the building is 30 degrees, and the angle of depression to the bottom of the lighthouse is 60 degrees. ### Step 2: Draw a Diagram Draw a vertical line for the building (60 m) and another vertical line for the lighthouse (height = h). Mark the top of the building as point A, the bottom as point B, the top of the lighthouse as point C, and the bottom of the lighthouse as point D. The horizontal distance from the building to the lighthouse is x. ### Step 3: Set Up the Right Triangles 1. **Triangle ABC** (for the angle of elevation): - Angle CAB = 30 degrees - Height of building (AB) = 60 m - Height of lighthouse (AC) = h - Therefore, the height difference (BC) = h - 60 m. 2. **Triangle BCD** (for the angle of depression): - Angle CBD = 60 degrees - Height of lighthouse bottom (BD) = 60 m (the height of the building). ### Step 4: Apply Trigonometric Ratios 1. For triangle ABC: \[ \tan(30^\circ) = \frac{BC}{AB} = \frac{h - 60}{x} \] We know that \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\), so: \[ \frac{1}{\sqrt{3}} = \frac{h - 60}{x} \implies x = \sqrt{3}(h - 60) \tag{1} \] 2. For triangle BCD: \[ \tan(60^\circ) = \frac{BD}{BC} = \frac{60}{x} \] We know that \(\tan(60^\circ) = \sqrt{3}\), so: \[ \sqrt{3} = \frac{60}{x} \implies x = \frac{60}{\sqrt{3}} \tag{2} \] ### Step 5: Equate the Two Expressions for x From equations (1) and (2): \[ \sqrt{3}(h - 60) = \frac{60}{\sqrt{3}} \] ### Step 6: Solve for h Multiply both sides by \(\sqrt{3}\): \[ 3(h - 60) = 60 \] Expanding gives: \[ 3h - 180 = 60 \] Adding 180 to both sides: \[ 3h = 240 \] Dividing by 3: \[ h = 80 \text{ m} \] ### Step 7: Find the Difference in Heights The difference between the height of the lighthouse and the height of the building is: \[ h - 60 = 80 - 60 = 20 \text{ m} \] ### Final Answer The difference between the height of the lighthouse and the building is **20 meters**. ---
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The angles of elevation oand depression of the top and bottom of a lighthouse from the top of a building, 60 m high, are 30^(@) and 60^(@) respectively. Find (i) the difference between the heights of the lighthouse and the building. (ii) distance between the lighthouse and the building.

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CBSE COMPLEMENTARY MATERIAL-SOME APPLICATIONS OF TRIGONOMETRY-LONG ANSWER TYPE QUESTIONS
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  8. As observed from the top of a lighthouse, 100 m above sea level, the a...

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  9. The angles of elevation and depression of the top and bottom of a ligh...

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  12. A 1.2 m tall girl spots a ballon moving with wind in a horizontal line...

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  13. The angle of elevation of cloud from a point 60 m above a lake is 30...

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  14. Two pillars of equal height stand on either side of a roadway which is...

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  15. The angle of elevation of the top of a tower from a certain point i...

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  16. A moving boat is observed from the top of a 150 m high cliff moving aw...

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  17. From the top of a 120 m hight tower a man observes two cars on the opp...

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  19. A window of a house is h metres above the ground. From the window, the...

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