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The tops of two towers of height x an...

The tops of two towers of height `x` and `y` , standing on level ground, subtend angles of `30o` and `60o` respectively at the centre of the line joining their feet, then find `x\ : y` .

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Knowledge Check

  • A tower of height h stands at a point O on the ground. Two poles of height a and b stand at the points A and B respectively such that O lies on the line joining A and B. If the angle of elevation of the top of the tower at the foot of one pole is ame as at the top of the other pole, then h is equal to

    A
    `(a+b)/(ab)`
    B
    `(ab)/(a+b)`
    C
    a + b
    D
    `(a + b)/(|a-b|)`

  • The angles of elevation of the top of a tower standing on a horizontal plane, from two points on a line passing through its foot at distances a and b, respectively, are complementary angles. If the line joining the two points subtends an angle theta at the top of the tower, then if a gt b, sin theta =

    A
    `(a-b)/(a+b)`
    B
    `(a+b)/(a-b)`
    C
    `(2 sqrt(ab))/(a+b)`
    D
    `(2 sqrt(ab))/(a-b)`

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