In the given figure, from a rectangular region ABCD with `AB=20cm` a right triangle AED with `AE=9cm` and `DE=12cm`, is cut off. On the other end, taking BC as diameter, a semicircle is added on outside the region. The area of the shaded region.
[Use `pi=3.14`]

In Fig. 15.103, from a rectangular region A B C D with A B=20\ c m , a right triangle A E D with A E=9\ c m and D E=12 c m , is cut off. On the other end, taking B C as diameter, a semicircle is added on outside the region. Find the area of the shaded region. (U s e\ \ pi=22//7)

In the adjoining figure, find the area of the shaded region (Use pi = 3.14 )

In figure , AB is a diameter of the circle, AC = 6cm and BC = 8cm . Find the area of the shaded region . (use pi= 3.14 )

In the figure given below, the diameter of bigger semicircle is 108 cm. What is the area of the shaded region ?

In the given figure, if AOB is diameter, then the area of shaded region is: [Use pi = 3.14 ]

In given figure a semicircle of radius 7cm is inscribed in a rectangle.Find the area of the shaded region.

In the figure, Delta ABC is in the semi-circle, find the area of the shaded region given that AB = BC = 4 cm. (use pi = 3.14 )

In Fig.12.33,ABC is a quadrant of a circle of radius 14cm and a semicircle is drawn with BC as diameter.Find the area of the shaded region.

In the given figure, PQ = 24 cm PR = 7 cm and O is the centre of the circle. Find the area of the shaded region. (Use pi = 3.14 )

In the given figure DeltaABC is a right angled triangle with /_B=90^(@),AB=48cm and BC=14cm . With AC as diameter a semicircle is drawn and with BC as radius, a quadrant of a circle is drawn. Find the area of the shaded region. [Use pi=22/7 ]