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If z= x+iy and the amplitude of (z-2-3i)...

If `z= x+iy` and the amplitude of `(z-2-3i)` is `(pi)/(4)`. Find the relation between x and y.

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To solve the problem, we start with the given information: Let \( z = x + iy \), where \( x \) and \( y \) are real numbers. We are given that the amplitude (or argument) of \( z - 2 - 3i \) is \( \frac{\pi}{4} \). ### Step 1: Express \( z - 2 - 3i \) We can rewrite \( z - 2 - 3i \) as: \[ z - 2 - 3i = (x + iy) - 2 - 3i = (x - 2) + i(y - 3) \] ### Step 2: Identify the real and imaginary parts From the expression \( (x - 2) + i(y - 3) \), we identify: - Real part: \( x - 2 \) - Imaginary part: \( y - 3 \) ### Step 3: Use the definition of amplitude The amplitude (or argument) of a complex number \( a + bi \) is given by: \[ \tan(\theta) = \frac{b}{a} \] In our case, we have: \[ \tan\left(\frac{\pi}{4}\right) = \frac{y - 3}{x - 2} \] ### Step 4: Evaluate \( \tan\left(\frac{\pi}{4}\right) \) We know that: \[ \tan\left(\frac{\pi}{4}\right) = 1 \] Thus, we can set up the equation: \[ 1 = \frac{y - 3}{x - 2} \] ### Step 5: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ y - 3 = x - 2 \] ### Step 6: Rearrange the equation Rearranging the equation, we can express the relation between \( x \) and \( y \): \[ y = x + 1 \] ### Final Relation The relation between \( x \) and \( y \) is: \[ y = x + 1 \] ---
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  2. If arg(z-1)=arg(z+3i), then find (x-1):y, where z=x+iy.

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  3. If z= x+iy and the amplitude of (z-2-3i) is (pi)/(4). Find the relatio...

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