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In what ratio y-axis divides the line se...

In what ratio y-axis divides the line segment joining the points (3,4) and (–2, 1)?

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To find the ratio in which the y-axis divides the line segment joining the points \( A(3, 4) \) and \( B(-2, 1) \), we can follow these steps: ### Step 1: Identify the Points Let \( A(3, 4) \) and \( B(-2, 1) \) be the two points. ### Step 2: Find the Equation of the Line We will use the two-point form of the equation of a line, which is given by: \[ y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1) \] Here, \( (x_1, y_1) = (3, 4) \) and \( (x_2, y_2) = (-2, 1) \). Substituting these values into the equation: \[ y - 4 = \frac{1 - 4}{-2 - 3} (x - 3) \] This simplifies to: \[ y - 4 = \frac{-3}{-5} (x - 3) \] \[ y - 4 = \frac{3}{5} (x - 3) \] ### Step 3: Rearranging the Equation Now, let's rearrange this equation: \[ y - 4 = \frac{3}{5}x - \frac{9}{5} \] Adding 4 to both sides: \[ y = \frac{3}{5}x + 4 - \frac{9}{5} \] Converting 4 to a fraction: \[ y = \frac{3}{5}x + \frac{20}{5} - \frac{9}{5} \] \[ y = \frac{3}{5}x + \frac{11}{5} \] ### Step 4: Find the Intersection with the Y-axis To find the point where the line intersects the y-axis, we set \( x = 0 \): \[ y = \frac{3}{5}(0) + \frac{11}{5} = \frac{11}{5} \] So, the coordinates of point \( C \) where the line intersects the y-axis are \( (0, \frac{11}{5}) \). ### Step 5: Use the Section Formula Let the y-axis divide the segment \( AB \) in the ratio \( m:n \). According to the section formula, the coordinates of point \( C \) can be expressed as: \[ C\left(0, \frac{11}{5}\right) = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \] Substituting \( A(3, 4) \) and \( B(-2, 1) \): \[ 0 = \frac{m(-2) + n(3)}{m+n} \] This gives us: \[ 0 = -2m + 3n \quad \text{(1)} \] For the y-coordinates: \[ \frac{11}{5} = \frac{m(1) + n(4)}{m+n} \] Multiplying both sides by \( m+n \): \[ 11(m+n) = 5(m + 4n) \] Expanding gives: \[ 11m + 11n = 5m + 20n \] Rearranging gives: \[ 6m - 9n = 0 \quad \text{(2)} \] ### Step 6: Solve the Equations From equation (1): \[ 2m = 3n \implies \frac{m}{n} = \frac{3}{2} \] Let \( m = 3k \) and \( n = 2k \) for some \( k \). ### Step 7: Conclusion Thus, the ratio in which the y-axis divides the line segment joining points \( A \) and \( B \) is: \[ m:n = 3:2 \]
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