Home
Class 11
MATHS
(x)/(a)+(y)/(b)=1 is intercept from of l...

`(x)/(a)+(y)/(b)=1` is intercept from of line. (Prove It)

Text Solution

AI Generated Solution

The correct Answer is:
To prove that the equation \(\frac{x}{a} + \frac{y}{b} = 1\) is the intercept form of a line, we can follow these steps: ### Step 1: Understand the Intercept Form of a Line The intercept form of a line is generally expressed as: \[ \frac{x}{a} + \frac{y}{b} = 1 \] where \(a\) is the x-intercept (the point where the line intersects the x-axis) and \(b\) is the y-intercept (the point where the line intersects the y-axis). ### Step 2: Identify the Intercepts From the equation \(\frac{x}{a} + \frac{y}{b} = 1\): - When \(y = 0\) (to find the x-intercept), we substitute \(y\) into the equation: \[ \frac{x}{a} + \frac{0}{b} = 1 \implies \frac{x}{a} = 1 \implies x = a \] Thus, the x-intercept is \((a, 0)\). - When \(x = 0\) (to find the y-intercept), we substitute \(x\) into the equation: \[ \frac{0}{a} + \frac{y}{b} = 1 \implies \frac{y}{b} = 1 \implies y = b \] Thus, the y-intercept is \((0, b)\). ### Step 3: Plot the Points Now, we can plot the points \((a, 0)\) and \((0, b)\) on the coordinate axis. These points will help us visualize the line. ### Step 4: Use the Two-Point Form of a Line The two-point form of a line passing through points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} \] In our case, we can denote: - \((x_1, y_1) = (a, 0)\) - \((x_2, y_2) = (0, b)\) Substituting these points into the two-point form: \[ \frac{y - 0}{b - 0} = \frac{x - a}{0 - a} \] This simplifies to: \[ \frac{y}{b} = \frac{x - a}{-a} \] ### Step 5: Rearranging the Equation Cross-multiplying gives: \[ y = -\frac{b}{a}(x - a) \] Expanding this: \[ y = -\frac{b}{a}x + b \] ### Step 6: Rearranging to the Intercept Form Now, we can rearrange this equation: \[ \frac{x}{a} + \frac{y}{b} = 1 \] This shows that the equation \(\frac{x}{a} + \frac{y}{b} = 1\) indeed represents a line in intercept form. ### Conclusion Thus, we have proven that the equation \(\frac{x}{a} + \frac{y}{b} = 1\) is the intercept form of a line. ---
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CBSE COMPLEMENTARY MATERIAL|Exercise SECTION-B (SHORT ANSWER TYPE QUESTIONS)|5 Videos
  • STRAIGHT LINES

    CBSE COMPLEMENTARY MATERIAL|Exercise SECTION-C (SHORT ANSWER TYPE QUESTIONS)|15 Videos
  • STRAIGHT LINES

    CBSE COMPLEMENTARY MATERIAL|Exercise SECTION-D (LONG ANSWER TYPE QUESTIONS )|23 Videos
  • STATISTICS

    CBSE COMPLEMENTARY MATERIAL|Exercise Section - D (Long Answer Type-II Questions) (6 Mark)|10 Videos
  • TRIGONOMETRIC FUNCTIONS

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER TYPE QUESTIONS|62 Videos

Similar Questions

Explore conceptually related problems

Intercept form of a straight line is (x)/(a)+(y)/(b) =1 ,a = intercept of x and b= intercept of y, a+b is called sum of intercepts, ab is called product of intercepts. Q.The equation of the straight line passing through (2,2) and having intercepts whose sum is -1 is

Put the equation (x)/(a)+(y)/(b)=1 to the slope intercept form and find its slope and y- intercept

If one diagonal of a square is the portion of the line (x)/(a)+(y)/(b)=1 intercepted by the axes,then the extremities of the other diagonal of the square are

Find the equations of the straight lines which pass through the origin and trisect the portion of the st.line (x)/(a)+(y)/(b)=1 , which is intercepted between the axes.

For a variable line (x)/(a)+(y)/(b)=1,a+b=10 the locus of mid point of the intercept of this line between coordinate axes is

If (x)/(l)+(y)/(m)=1 is any line passing through the intersection point of the lines (x)/(a)+(y)/(b)=1 and (x)/(b)+(y)/(a)=1 then prove that (1)/(l)+(1)/(m)=(1)/(a)+(1)/(b)

The variable line (x)/(a)+(y)/(b)=1 is such that a+b=10 .The locus of the mid-point of the portion of the line intercepted between the axes is x+y=k then k=

Find the equation of the straight line through the point P(a,b) parallel to the line x/a+y/b = 1 also find the intercepts made by it on the axes .

intercepts cut by line 12x-9y=108

A function f is defined by f(x)=int_(0)^(x)(dt)/(1+t^(2)) The normal line to y=f(x) at x=1 has x -intercept equal to X and y -intercept equal to Y then