Home
Class 11
MATHS
if the eccentricity of the hyperbola is ...

if the eccentricity of the hyperbola is `sqrt2`. then find the general equation of hyperbola.

Text Solution

AI Generated Solution

The correct Answer is:
To find the general equation of a hyperbola given that its eccentricity \( e \) is \( \sqrt{2} \), we can follow these steps: ### Step 1: Recall the formula for eccentricity of a hyperbola The eccentricity \( e \) of a hyperbola is given by the formula: \[ e = \frac{\sqrt{a^2 + b^2}}{a} \] where \( a \) and \( b \) are the semi-major and semi-minor axes respectively. ### Step 2: Substitute the value of eccentricity Given that \( e = \sqrt{2} \), we can substitute this into the eccentricity formula: \[ \sqrt{2} = \frac{\sqrt{a^2 + b^2}}{a} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ \sqrt{2}a = \sqrt{a^2 + b^2} \] ### Step 4: Square both sides to remove the square root Squaring both sides results in: \[ 2a^2 = a^2 + b^2 \] ### Step 5: Rearrange the equation to find a relationship between \( a^2 \) and \( b^2 \) Rearranging the equation gives: \[ 2a^2 - a^2 = b^2 \implies a^2 = b^2 \] ### Step 6: Write the general equation of the hyperbola The standard equation of a hyperbola is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] Since we found that \( a^2 = b^2 \), we can denote \( a^2 \) as \( k \) (where \( k \) is a positive constant). Thus, the equation becomes: \[ \frac{x^2}{k} - \frac{y^2}{k} = 1 \] ### Step 7: Simplify the equation This simplifies to: \[ x^2 - y^2 = k \] ### Step 8: General form of the hyperbola Thus, the general equation of the hyperbola can be expressed as: \[ x^2 - y^2 = a^2 \quad \text{(where } a^2 = k \text{)} \]
Promotional Banner

Topper's Solved these Questions

  • COORDINATE GEOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise section(C) (Short Answer Type Question) (4 Marks)|17 Videos
  • COORDINATE GEOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise section(D) (Long Answer Type Questions ) (6 Marks)|21 Videos
  • COORDINATE GEOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise section(D) (Long Answer Type Questions ) (6 Marks)|21 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    CBSE COMPLEMENTARY MATERIAL|Exercise Short Answer Type Questions|49 Videos
  • INTRODUCTION TO THREE-DIMENSIONAL COORDINATE GEOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER TYPE QUESTIONS|20 Videos

Similar Questions

Explore conceptually related problems

let the eccentricity of the hyperbola x^2/a^2-y^2/b^2=1 be reciprocal to that of the ellipse x^2+4y^2=4. if the hyperbola passes through a focus of the ellipse then: (a) the equation of the hyperbola is x^2/3-y^2/2=1 (b) a focus of the hyperbola is (2,0) (c) the eccentricity of the hyperbola is sqrt(5/3) (d) the equation of the hyperbola is x^2-3y^2=3

The eccentricity of rectangular hyperbola is sqrt(2)

If the eccentricity of a hyperbola is 2, then find the eccentricity of its conjugate hyperbola.

The eccentricity of a rectangular hyperbola, is

If the eccentricity of a hyperbola is sqrt(3) , the eccentricity of its conjugate hyperbola, is

The eccentricity of the hyperbola x ^(2) - y^(2) =25 is

If PQ is a double ordinate of the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 such that OPQ is an equilateral triangle,O being the center of the hyperbola, then find the range of the eccentricity e of the hyperbola.

Find the eccentricity of hyperbola x^(2)-9y^(2)=1 .

Find the eccentricity of the hyperbola 9y^(2)-4x^(2)=36