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Find the Standard Deviation of First 10 Even Natural numbers.

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To find the standard deviation of the first 10 even natural numbers, we will follow these steps: ### Step 1: Identify the first 10 even natural numbers The first 10 even natural numbers are: \[ 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 \] ### Step 2: Calculate the mean (average) The mean \( \bar{x} \) is calculated using the formula: \[ \bar{x} = \frac{\sum x_i}{n} \] where \( n \) is the number of observations and \( x_i \) are the observations. Calculating the sum: \[ \sum x_i = 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110 \] The number of observations \( n = 10 \). Now, calculate the mean: \[ \bar{x} = \frac{110}{10} = 11 \] ### Step 3: Calculate the squared differences from the mean Next, we calculate the squared differences from the mean for each observation: \[ (x_i - \bar{x})^2 \] Calculating each squared difference: - For \( 2 \): \( (2 - 11)^2 = (-9)^2 = 81 \) - For \( 4 \): \( (4 - 11)^2 = (-7)^2 = 49 \) - For \( 6 \): \( (6 - 11)^2 = (-5)^2 = 25 \) - For \( 8 \): \( (8 - 11)^2 = (-3)^2 = 9 \) - For \( 10 \): \( (10 - 11)^2 = (-1)^2 = 1 \) - For \( 12 \): \( (12 - 11)^2 = (1)^2 = 1 \) - For \( 14 \): \( (14 - 11)^2 = (3)^2 = 9 \) - For \( 16 \): \( (16 - 11)^2 = (5)^2 = 25 \) - For \( 18 \): \( (18 - 11)^2 = (7)^2 = 49 \) - For \( 20 \): \( (20 - 11)^2 = (9)^2 = 81 \) ### Step 4: Sum the squared differences Now, we sum all the squared differences: \[ \sum (x_i - \bar{x})^2 = 81 + 49 + 25 + 9 + 1 + 1 + 9 + 25 + 49 + 81 \] Calculating this gives: \[ \sum (x_i - \bar{x})^2 = 81 + 49 + 25 + 9 + 1 + 1 + 9 + 25 + 49 + 81 = 330 \] ### Step 5: Calculate the variance The variance \( \sigma^2 \) is given by: \[ \sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n} \] Substituting the values: \[ \sigma^2 = \frac{330}{10} = 33 \] ### Step 6: Calculate the standard deviation The standard deviation \( \sigma \) is the square root of the variance: \[ \sigma = \sqrt{33} \] Thus, the standard deviation of the first 10 even natural numbers is: \[ \sqrt{33} \]
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