An urn contains 6 red and 3 black balls. Two balls are randomly drawn. Let x presents the number of black balls. What are the possible value of x?

Answer

To solve the problem, we need to determine the possible values of \( x \), where \( x \) represents the number of black balls drawn from the urn containing 6 red and 3 black balls when two balls are drawn.

### Step-by-Step Solution:

1. **Identify the Total Number of Balls:**
- The urn contains a total of \( 6 \) red balls and \( 3 \) black balls.
- Therefore, the total number of balls in the urn is:
\[ 6 + 3 = 9 \text{ balls} \]

2. **Define the Random Variable \( x \):**
- The random variable \( x \) represents the number of black balls drawn when two balls are selected from the urn.

3. **Determine the Possible Values of \( x \):**
- Since we are drawing two balls, the possible scenarios for the number of black balls drawn can be:
- \( x = 0 \): No black balls are drawn (both balls drawn are red).
- \( x = 1 \): One black ball is drawn and one red ball is drawn.
- \( x = 2 \): Two black balls are drawn.

4. **List the Possible Values of \( x \):**
- From the above scenarios, we can conclude that the possible values of \( x \) are:
\[ x = 0, 1, 2 \]

### Final Answer:
The possible values of \( x \) are \( 0, 1, \) and \( 2 \).