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The error in the measurement of radius o...

The error in the measurement of radius of a shpere if 2%. What would be the error in the volume of the sphere?

Text Solution

Verified by Experts

`v=(4)/(3)piR^(3)`
`(DeltaV)/(V)=3(DeltaR)/(R)implies(DeltaV)/(V)%=3xx2%=6%`
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