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Given : force = (alpha)/("density" + bet...

Given : force `= (alpha)/("density" + beta^3).` What are the dimensions of `alpha, beta ?`

A

`ML^(–2) T^(–2) , ML^(–1//3)`

B

`M^(2) L^(4) T^(–2), M^(1//3) L^(–1)`

C

`M^(2) L^(–2) T^(–2), M^(1//3) L^(–1)`

D

`M^(2) L^(–2) T^(–2), M L^(–3)`

Text Solution

Verified by Experts

The correct Answer is:
C

Dimension of `β^(3)` = dimension of density
Solve, `beta=[M^(1//3)L^(-1)]`
Force = `(alpha)/("density")`
`alpha` = Force `xx` density
`=[MLT^(-2)ML^(-3)]`
`=[M^(2)L^(-2)T^(-2)]`
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