Three blocks of masses `m_1= 10 kg, m_2= 20kg,m_3= 30kg` are connected by strings on smooth horizontal surface and pulled by a force of 60 N. Find the acceleration of the system and tensions in the string.

Explanation

All the blocks more with common acceleration a under the force F = 60 N.
`F= (m_1 + m_2 + m_3)a`
`a=(F)/((m_(1)+m_(2)+m_(3))=1m//s^(2)`
To determine, `T_1 to` Free body diagram of mass `m_1.`

`T_1= m_1a = 10xx 1= 10 N`
To determine, `T_2 -` Free body diagram of `m_3.`

`F-T_(2)=m_3a`
Solving, we get `T_(2)=30N`