Three forces vecA =hati+hatj-hatk, vecB=...

Three forces `vecA =hati+hatj-hatk, vecB=2hati-hatj+3hatk and vecC` are acting on a body to keep it in equilibrium. Then `vecC` is

A

`-(3hati+4hatk)`

B

`-(4hati+3hatk)`

C

`3hati+4hatk`

D

`2hati+3hatk`

Text Solution

Verified by Experts

The correct Answer is:

A

Since body is in equilibrium
`vecA +vecB+vecC=vecO`
`vecC=-(vecA+vecB)=-[hati+hatj+hatk+2hati-hatj+3hatk]`
`=-[3hati+0hatj+4hatk)=-(3hati+4hatk)`

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