One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is `(gamma=3//5)`

Options

A. `-20 KJ`
B. 20 J
C. `-12 KJ`
D. 20 KJ

Answer

A

Explanation

Change in internal energy
`DeltaU = nC_v DeltaT and T = (PV)/(nR)`
`DeltaT = T_2 -T_1 = (P_2V_2-P_1V_1)/(nR) , C_v =R/(gamma-1)`
`DeltaU = (nR)/(gamma-1)((P_2V_2-P_1V_1)/(nR))=(P_2V_2-P_1V_1)/(gamma-1)`
`= (5xx4-2xx6)/(3/5-1) = (20-12)/(-2//5)=(-8)/(2//5)- 20 KJ`