A Carnot engine, having an efficiency of `eta=1//10` as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is

Options

A. 99 J
B. 90 J
C. 1 J
D. 100 J

Answer

B

Explanation

Here `eta=1/10 , W=10 J theta_2 = ? `
`beta=(1-eta)/eta=(1-1//10)/(1//10)=9`
As ` beta = theta_2 / W " or " theta_2 = 90J`