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A proton and deutron are accelerated thr...

A proton and deutron are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and (b) less momentum? Give reasons to justify your answer.

Text Solution

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de Broglie wavelength, `lambda=h/sqrt(2mqV)`
Here V same for proton and deutron.
As mass of proton < mass of deutron and `q_p = q_d`. Therefore, `lambda_p > lambda_d` for same accelerating potential.
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