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A charge is distributed uniformly over a...

A charge is distributed uniformly over a ring of radius ‘a’. Obtain an expression for the electric intensity E at a point on the axis of the ring. Hence show that for points at large distances from the ring, it behaves like a point charge.

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To solve the problem of finding the electric intensity \( E \) at a point on the axis of a uniformly charged ring, we will follow these steps: ### Step 1: Understand the Configuration Consider a ring of radius \( a \) with a uniform charge \( Q \) distributed over it. Let \( P \) be a point on the axis of the ring at a distance \( x \) from the center of the ring. ### Step 2: Define Linear Charge Density Let \( \lambda \) be the linear charge density of the ring, given by: \[ ...
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A charge is distributed uniformaly over is ring of radius 'a' .Obtain an expression for the electric intensity E at a point on the axis of the ring. Hence show that for points at large distances from the ring, it behaves like a point charge.

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Knowledge Check

  • A ring of radius a contains a charge q distributed. uniformly ober its length. Find the electric field at a point. on the axis of the ring at a distance x from the centre.

    A
    `(kq^2)/(x(a^2+x^2)^(3/2))`
    B
    `(2kq^2x)/(a^2+x^2)^(3/2)`
    C
    `(kq^2x)/(a^2+x^2)^(3/2)`
    D
    `(kq^2)/(2x(a^2+x^2)^(3/2))`
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