`lim_(x->0) (sin^(-1)x+3x)/(tanx+2sin(1/2sin^(- 1)x)[3-4sin^2(1/2sin^(- 1)x)])=`

Lt_(x to 0)(sin^(-1)x+3x)/(tanx+2sin((1)/(2)sin^(-1)x)[3-4"sin"^(2)((1)/(2)sin^(-1)x)])=

lim_(x->1/sqrt2) (x-cos(sin^-1 x))/(1-tan(sin^-1x))

lim_(x->0)((1-cos2x)sin5x)/(x^2sin3x)

lim_(x rarr 0) (tan (sin^(-1) 3x))/(sin^(-1) (2 tan x)) =

lim_(x rarr 0) (tan^(-1)3x-4tanx)/(4 sin^(-1) 2x -7x) =

3. lim_(x rarr0)(sin x sin^(-1)x)/(x^(2))

lim_(x rarr pi/6) (2sin^(2)x + sin x-1)/(2sin^(2)x-3sinx -1) =

Evaluate: lim_(n rarr0)(1^(1/sin^(2)x)+2sin^((1)/(2sin^(2)x))+...+n^(1/sin^(2)x))^(sin^(2)x)

The value of lim_(x->0)((sinx-tanx)^2-(1-cos2x)^4+x^5)/(7(tan^(- 1)x)^7+(sin^(- 1)x)^6+3sin^5x) equal to :