[" Find "x" if "ln e^((2cos^(2)x-1))=cos x," for "0

Find x if In e^(2cos^(2)x-1)=cos x, for 0

int sin2x.log cos xdx is equal to 1) cos^(2)x((1)/(2)+log cos x)+k 2) cos^(2)x*log cos x+k 3) cos^(2)x((1)/(2)-log cos x)+k 4) cos^(2)x+log cos x+k

Evaluate : lim_(x to 0) (e^(cos x)-1)/(cos x)

int(1)/(x cos^(2)(log_(e)x))dx

int(1)/(x cos^(2)(log_(e)x))dx

If "log"_(2) "sin" x - "log"_(2) "cos" x - "log"_(2) (1-"tan"^(2) x) =-1 , then x =

If "log"_(2) "sin" x - "log"_(2) "cos" x - "log"_(2) (1-"tan"^(2) x) =-1 , then x =

Find (dy)/(dx), if 1) y=4^(log_(2)sin x)+9^(log_(3)cos x) 2) y=e^(2(log sec x))-9^(log_(3)tan x)