Home
Class 10
MATHS
" (3) "(148)/(x)+(231)/(y)=(527)/(xy);(2...

" (3) "(148)/(x)+(231)/(y)=(527)/(xy);(231)/(x)+(148)/(y)=(610)/(xy)

Promotional Banner

Similar Questions

Explore conceptually related problems

Solve the following simultaneous equations. (148)/(x) + (231)/(y) = (527)/(xy) , (231)/(x) + (148)/(y) = (610)/(xy)

Solve the following simultaneous equations (148)/x + (231)/y = (527)/(xy) , (231)/x + (148)/y = (610)/(xy)

Solve the following simultaneous equations 148/x+231/y=527/(xy),231/x+148/y=610/(xy) .

(xy)/(x+y)=(6)/(5)(xy)/(y-x)=6

(xy)/(x+y)=6/5 ; (xy)/(y-x)=6

(dy)/(dx)=(xy+y)/(xy+x)

The average of the reciprocals of x and y is (a) ((x+y))/((x-y)) (b) ((x+y))/(2xy) (c) (2(x+y))/(xy) (d) (2xy)/((x+y))

(dy)/(dx)+(xy+y)/(xy+x)=0

(xy)/(x-y)=(1)/(2);(xy)/(x+y)=(1)/(5) wherex +y!=0;x-y!=0

sin(xy) + (x)/(y) = x^(2) - y