Two charges are separated by a , distance 1m .When a dielectric slab of thickness 40cm is introduced between , them the force becomes half its previous value. The dielectric constant of medium is

Two point charges placed at a distance of 0.20m in air repel each other with a certain force.When a dielectric slab of thickness 0.08m is introduced in between the charges,the force of interaction is half of its previous value.The value of dielectric constant of slab is ,,,..

The capacitance of a parallel plate capacitor is 10muF . When a dielectric plate is introduced in between the plates, its potential becomes 1/4th of its original value. What is the value of the dielectric constant of the plate introduced?

The plates in a parallel plates capacitor are seperated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness (3d)/5 is introduced between the plates. What is the dielectric constant of the dielectric slab ?

The plates of a parallel plate capacitor are separated by a distance d = 1 cm . Two parallel sided dielectric slabs of thickness 0. 7cm and 0.3cm fill the space between the plates. If the dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 440V is applied across the plates. Find (a) The electric field intensities in each of the slabs. (b) The ratio of electric energies stored in the first to that in the second dielectric slab.

Capacitance of a capacitor becomes 7/6 times of its original value if a dielectric slab of thickess t=2/4d is introduced in between the plates, d is the separation between the plates. The dielectric constant of the dielectric slab is

The capacitance of a capacitor becomes 7/6 times its original value if a dielectric slab of thickness t=(2)/(3) is introduced between its plates, where d is the separation between its plates, what is the dielectric constant of the slab?

A parallel plate capacitor has a capacity C. The separation between the plates is doubled and a dielectric medium is introduced between the plates. If the capacity now becomes 2C, the dielectric constant of the medium is

Two charges placed in air repel each other by a force of 10^(-4)N . When oil is introduced between the charges, then the force becomes 2.5 xx 10^(-5)N The dielectric constant of oil is

Two charges 4 cm apart repel each other with a force of 2xx10^(-2) N in air. When a dielectric slab of thickness 1 cm is placed between them, The force is reduced to 1.5xx10^(-2) N. Calculate the permittivity of the dielectric.

A parallel plate air capacitor has capacitance 18 mu F. If the distance between the plates is tripled and dielectric medium is introduced the capacitance becomes 72 mu F. The dielectric constant of the medium is :-