The line `y=x` is a tangent at `(0,0)` to a circle of radius unity. The center of the circle is

If the line x+3y=0 is the tangent at (0,0) to the circle of radius 1, then the centre of one sum circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. Then find the radius of the circle.

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. The radius of the circle is 3sqrt(5)(b)5sqrt(3)(c)2sqrt(5)(d)5sqrt(2)

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4 The radius of the circle is:

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is :

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the centre of the circle lies on x-2y=4. The square of the radius of the circle is

The line 2x-3y+1=0 is tangent to a circle S=0 at (1,1). If the radius of the circle is sqrt(13). Find theequation of the circle S.

Centre of a circle of radius 4sqrt(5) lies on the line y=x and satisfies the inequality 3x+6y > 10. If the line x+2y=3 is a tangent to the circle, then the equation of the circle is