In 2.6 gm of `FeSO_(4).6H_(2)O` (At wt of fe =56):

In 2.6 Kg of FeSO_(4).6H_(2)O (At wt of fe =56):

FeSO_(4)+NO+H_(2)O to

The amount of FeSO_(4).7H_(2)O to be weighted to prepare a solution of 100 ml of 0.1 M concentration is (Mol.wt.of FeSO_(4) . 7H_(2)0=278)

The weight in grams of K_(2)Cr_(2)O_(7) required to oxidise Fe_(21) ions present in 7.6 gram of FeSO_(4) to Fe^(3+) if the reaction is carried out in an acidic medium is

5 g of SrCl_(2).6H_(2)O gave 3.442 gm of dry SrSO_(4) , then eq. wt. of Sr will be

5 g of SrCl_(2).6H_(2)O gave 3.442 gm of dry SrSO_(4) , then eq. wt. of Sr will be

The molecular formula of Mohr's salt is (NH_(4))_(2)SO_(4)FeSO_(4).6H_(2)O Find the number of atoms of each element.