Let f:[-pi/3,(2pi)/3]vec[0,4] be a funct...

Let `f:[-pi/3,(2pi)/3]vec[0,4]` be a function defined as `f(x)=sqrt(3)sinx-cosx+2.` Then `f^(-1)(x)` is given by `sin^(-1)((x-2)/2)-pi/6` `sin^(-1)((x-2)/2)+pi/6` `(2pi)/3+cos^(-1)((x-2)/2)` (d) none of these

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