14*x^(2)-x-a(a+1)=0

If roots of equation 8x^(3)-14x^(2)+7x-1=0 are in geometric progression,then toots are

I. 15x^(2) - 2x-1=0 II. y^(2) - 9y+14 = 0

Prove that sinfrac {pi}{14} is a root of the equation 8x^(3) -4x^(2) - 4x +1 = 0 .

2(x^(2)+(1)/(x^(2)))-9(x+(1)/(x))+14=0

(i) x^(2) - 5x-14 = 0 (ii) 2y^(2) +11y + 14 = 0

Suppose that two persons A and B solve the equation x^(2)+ax+b=0 . While solving A commits a mistake in constant term and find the roots as 6 and 3 and B commits a mistake in the coefficient of x and finds the roots as -7and-2 .Then , the equation is a) x^(2)+9x+14=0 b) x^(2)-9x+14=0 c) x^(2)+9x-14=0 d) x^(2)-9x-14=0

x^(18) + x^(12)=0, x^(20) + x^(14)= 0

Solve for x:2(x^2+1/(x^2))-9(x+1/x)+14=0 .

If x^(2)-3 x+1=0 , then (x^(14)+1)/(x^(7))=