" (iv) "(x)/(a)+(y)/(b)=2;ax-by=(a^(2)-b^(2))

(x)/(a)-(y)/(b)=0,ax+by=a^(2)+b^(2)

Solve for xandy: (x)/(a)+(y)/(b)=2,ax-by=a^(2)-b^(2)

Solve: (x)/(a)+(y)/(b)=2,quad ax-by=a^(2)-b^(2)

Solve the following system of equations by method of cross-multiplication: (x)/(a)+(y)/(b)=2,quad ax-by=a^(2)-b^(2)

Answer each question by selecting the proper alternative from those given below each question so as to make the statement true: The solution of the equations (x)/(a)+(y)/(b)=2 and ax-by=a^(2)-b^(2) is ……………. a) x = a , y = b b) x = −a , y = −b c) x = a , y = −b d) x = −a , y = b

x+y=a+b,ax-by=a^(2)-b^(2)

The value of y which satisfies (x)/(a)=(y)/(b) and ax+by=a^(2)+b^(2) is

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

Solve the following simultaneous linear equations in two linear variables by the method of cross-multiplication : x/a+y/b=2, ax-by=a^(2)-b^(2)

The locus of the midpoints of the chords of the circle x^(2)+y^(2)-ax-by=0 which subtend a right angle at ((a)/(2),(b)/(2)) is ax+by=0ax+by=a^(2)=b^(2)x^(2)+y^(2)-ax-by+(a^(2)+b^(2))/(8)=0x^(2)+y^(2)-ax-by-(a^(2)+b^(2))/(8)=0