If `f(x+y)=f(x)+f(y)-x y-1AAx , y in Ra n df(1)=1,` then the number of solution of `f(n)=n , n in N ,` is 0 (b) 1 (c) 2 (d) more than 2

If f(x) is a real valued functions satisfying f(x+y) = f(x) +f(y) -yx -1 for all x, y in R such that f(1)=1 then the number of solutions of f(n) = n,n in N , is

If f(x+y)=f(x)+f(y) -xy -1 for all x, y in R and f(1)=1 then f(n)=n, n in N is true if

If f(x+y)=f(x)dotf(y),\ AAx in R\ a n df(x) is a differentiability function everywhere. Find f(x) .

If f_(1)(x)=|x|-2| and f_(2)(x)=|f_(n-1)(x) for all n>=2,n in N, then number of solution of the equation f_(2015)(x)=2 is

If f(x+y)=f(x)*f(y) and f(1)=4. Find sum_(r=1)^(n)f(r)

If f(x+y+1)={sqrt(f(x))+sqrt(f(y))}^(2) and f(0)=1AA x,y in R, determine f(n),n in N in N

If f(x+y)=f(x)-f(y)+2xy-1AAx,yinR . Also if f(x) is differentiable and f'(0)=b also f(x)gt0AAx , then the set of values of b

Let f be a function satisfying f(x+y)=f(x)+f(y) for all x,y in R. If f(1)=k then f(n),n in N is equal to