19times(12+18)=(19times12)+(19times

Prove that 19times[5+(-2)]=[19times5]+[19times(-2)]

If sum_(k=1)^(12)12k^(12)C_(k)^(11)C_(k-1) is equal to (12times21times19times)/(11!)times2^(12)times P then P is

If sum_(k=1)^(12)12kquad 12C_(k)^quad 11C_(k-1) is equal to (12times21times19times......3)/(11!)times2^(12)times P then P is

Give the result without performing the operations using the given information. 28times19=532 then 19times28 ___

Solve: 19.7times4

Fill in the blanks: 19 times 101= _______ times 19

Verify and state the property used in each of the following. (-7) times (19+4)=[(-7) times 19]+[(-7) times 4]

Which of the following cannot be the charge on a particle? [-3.2times10^(-19)C],[4.8times10^(-19)C],[1.2times10^(-19)C],[1.6times10^(-19)C]