`(x+1)^(log(x+1))=100(x+1)(base' i s'10)`

Solve (x+1)^(log_(10)(x+1))=100(x+1)

Solve (x+1)^(log_(10) (x+1))=100(x+1)

Solve (x+1)^(log_(10) (x+1))=100(x+1)

If (x+1)^((log)_(10)(x+1))=100(x+1), then all the roots are positive real numbers all the roots lie in the interval (0,100) all the roots lie in the interval [-1,99]

If (x+1)^((log)_(10)(x+1))=100(x+1), then all the roots are positive real numbers all the roots lie in the interval (0,100) all the roots lie in the interval [-1,99]

If (x+1)^((log)_(10)(x+1))=100(x+1), then

140*x^(1)+log x=10x

Suppose x;y;z>0 and are not equal to 1 and log x+log y+log z=0. Find the value of x(1)/(log y)+(1)/(log z)xx y^((1)/(log z)+(1)/(log x))xx(1)/(log x)+(1)/(log y) (base 10)