Home
Class 13
CHEMISTRY
[" The decomposition of a hydrocarbon fo...

[" The decomposition of a hydrocarbon follows the equation "],[k=(4.5times10^(11)s^(-1))e^(-25000times17)." What will be the value of activation energy? "]

Promotional Banner

Similar Questions

Explore conceptually related problems

The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T) Calculate E_(a) .

The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T) Calculate E_(a) .

The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T) Calculate E_(a) .

The decomposition of hydrocarbon follows the equation k = (4.5 × 10^(11) S^(-1)) e^(-28000K/T) Calculate E_a

The decomposition of hydrocarbon follows the equation k =(4.5xx10^(11)s^(-1))e^(-28000K//T) . Calculate E_(a) .

The decomposition of a hydrocarbon follows the equationk = (4.5 xx 10 ^(11) s^(-1) )e^(-28000) K/T. Calculate E_a .