Hydrogen peroxide oxidises thiosulphate ion to-

Options

A. `SO_(3)^(2-)`
B. `SO_(4)^(2-)`
C. `S_(4)O_(6)^(2-)`
D. `S`

Answer

To solve the question regarding the oxidation of thiosulphate ion by hydrogen peroxide, we can follow these steps:

### Step 1: Identify the Thiosulphate Ion
The thiosulphate ion is represented as \( \text{S}_2\text{O}_3^{2-} \). This is the starting point of our reaction.

### Step 2: Understand the Role of Hydrogen Peroxide
Hydrogen peroxide (\( \text{H}_2\text{O}_2 \)) acts as an oxidizing agent. This means it has the ability to accept electrons from other substances, thereby oxidizing them.

### Step 3: Write the Reaction
When thiosulphate ion reacts with hydrogen peroxide, it undergoes oxidation. The reaction can be expressed as:
\[ \text{S}_2\text{O}_3^{2-} + \text{H}_2\text{O}_2 \rightarrow \text{SO}_4^{2-} + \text{H}_2\text{O} + \text{S} \]
In this reaction, thiosulphate is oxidized to form sulfate (\( \text{SO}_4^{2-} \)).

### Step 4: Identify the Products
From the reaction, we can see that the thiosulphate ion is converted into sulfate ion (\( \text{SO}_4^{2-} \)). Other products may include water and elemental sulfur, but the main focus is on the sulfate ion.

### Step 5: Conclusion
Based on the reaction and the products formed, we conclude that hydrogen peroxide oxidizes thiosulphate ion to sulfate ion (\( \text{SO}_4^{2-} \)).

### Final Answer
The correct answer is \( \text{SO}_4^{2-} \).

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