In the following reactions , products (X) and (Y) respectively are
`underset(("hot and conc"))(NaOH)+Cl_2rarr(X)+` side products
`underset(("dry"))(Ca(OH)_2)+Cl_2rarr(Y)+` side products

Options

A. `NaOCl and Ca(ClO_3)_2`
B. `NaClO_3 and Ca(OCl)_2`
C. `NaOCl and Ca(OCl)_2`
D. `NaClO_3 and Ca(ClO_3)_2`

Answer

To solve the problem, we need to analyze the two reactions involving sodium hydroxide (NaOH) and calcium hydroxide (Ca(OH)₂) with chlorine gas (Cl₂) to determine the products (X) and (Y) respectively.

### Step-by-Step Solution:

1. **Reaction of Hot and Concentrated NaOH with Cl₂**:
- When hot and concentrated NaOH reacts with Cl₂, it undergoes a specific reaction that produces sodium chloride (NaCl) and sodium chlorate (NaClO₃).
- The balanced chemical equation for this reaction is:
\[ 6 \text{NaOH} + 3 \text{Cl}_2 \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2\text{O} \]
- From this reaction, we can identify that the primary product (X) is **sodium chlorate (NaClO₃)**.

2. **Reaction of Dry Ca(OH)₂ with Cl₂**:
- When dry calcium hydroxide (Ca(OH)₂) reacts with Cl₂, it forms calcium oxychloride (Ca(OCl)₂) initially, which can further react to form calcium chlorate (Ca(ClO₃)₂).
- The balanced equation for this reaction is:
\[ 2 \text{Ca(OH)}_2 + 2 \text{Cl}_2 \rightarrow 2 \text{Ca(OCl)}_2 + 2 \text{H}_2\text{O} \]
- The calcium oxychloride (Ca(OCl)₂) can then undergo further reactions, leading to:
\[ 2 \text{Ca(OCl)}_2 \rightarrow \text{Ca(ClO}_3)_2 + 5 \text{CaCl}_2 \]
- Thus, the primary product (Y) from this reaction is **calcium chlorate (Ca(ClO₃)₂)**.

3. **Final Products**:
- From the above reactions, we conclude:
- Product (X) from the reaction of hot and concentrated NaOH with Cl₂ is **NaClO₃**.
- Product (Y) from the reaction of dry Ca(OH)₂ with Cl₂ is **Ca(ClO₃)₂**.

### Summary of Products:
- **X = NaClO₃**
- **Y = Ca(ClO₃)₂**