A hydrocarbon `(A) C_nH_(2n-4)` on ozonolysis gives `(CH_3)_2CHCH_2CHO, 2 OH"CC"H_2CH_2CHO and CH_3COCH_3` The value of n is

Answer

To solve the problem, we need to determine the value of \( n \) in the hydrocarbon \( C_nH_{2n-4} \) based on the products formed during ozonolysis.

### Step-by-Step Solution:

1. **Identify the Degree of Unsaturation**:
The degree of unsaturation (DU) can be calculated using the formula:
\[ \text{DU} = \frac{2C + 2 + N - H - X}{2} \]
where \( C \) is the number of carbon atoms, \( H \) is the number of hydrogen atoms, \( N \) is the number of nitrogen atoms, and \( X \) is the number of halogens.

For our hydrocarbon \( C_nH_{2n-4} \):
- \( C = n \)
- \( H = 2n - 4 \)
- \( N = 0 \)
- \( X = 0 \)

Plugging these values into the formula:
\[ \text{DU} = \frac{2n + 2 - (2n - 4)}{2} = \frac{2n + 2 - 2n + 4}{2} = \frac{6}{2} = 3 \]

2. **Interpret the Degree of Unsaturation**:
A degree of unsaturation of 3 indicates that there are 3 double bonds (or rings) in the molecule. This means that the hydrocarbon could have multiple double bonds or rings.

3. **Analyze the Ozonolysis Products**:
The ozonolysis of the hydrocarbon yields the following products:
- \( (CH_3)_2CHCH_2CHO \) (an aldehyde)
- \( 2 \text{OH}CC\text{H}_2CHO \) (another aldehyde)
- \( CH_3COCH_3 \) (a ketone)

The presence of 3 products suggests that the original hydrocarbon had enough double bonds to produce these carbonyl compounds.

4. **Determine the Structure of Hydrocarbon**:
Given that the degree of unsaturation is 3, we can deduce that the hydrocarbon likely has multiple double bonds. The products indicate that the hydrocarbon could be a diene or a triene.

5. **Count the Carbon Atoms**:
From the products, we can infer the structure of the hydrocarbon. The products suggest that the hydrocarbon has a total of 16 carbon atoms. To verify:
- The first product has 5 carbons.
- The second product has 5 carbons.
- The third product has 3 carbons.
- The remaining carbons are likely part of the original hydrocarbon structure.

Therefore, we can conclude that the total number of carbon atoms in the hydrocarbon \( A \) is 16.

6. **Calculate \( n \)**:
Since we have established that the hydrocarbon is \( C_nH_{2n-4} \) and we found \( n = 16 \):
\[ n = 16 \]

### Final Answer:
The value of \( n \) is \( 16 \).

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