The number of carbonyl carbon in the products X is
Propyne `underset(Zn//H_2O)overset(O_3//CH_2CL_2,Delta)rarrX`

Answer

To solve the problem, we need to analyze the reaction of propyne with ozone (O3) followed by a reductive workup with zinc and water (Zn/H2O). The goal is to determine the number of carbonyl carbons in the product X.

### Step-by-Step Solution:

1. **Identify the Structure of Propyne**:
Propyne has the molecular formula C3H4 and its structure can be represented as:
\[ \text{CH}_3-\text{C} \equiv \text{C} \]

2. **Ozonolysis Reaction**:
When propyne undergoes ozonolysis, the triple bond reacts with ozone (O3). The reaction involves the formation of an ozonide intermediate. The triple bond breaks and forms a double bond with oxygen. The ozonolysis of propyne can be represented as:
\[ \text{CH}_3-\text{C} \equiv \text{C} + O_3 \rightarrow \text{Ozonide} \]

3. **Formation of Ozonide**:
The ozonide is formed when the ozone reacts with the propyne. The structure of the ozonide can be complex, but it generally contains a cyclic structure with oxygen atoms.

4. **Reductive Workup**:
The ozonide is then treated with zinc and water (Zn/H2O), which reduces the ozonide to carbonyl compounds. In this case, we will get one ketone and one aldehyde from the ozonide:
\[ \text{Ozonide} \xrightarrow{\text{Zn/H}_2\text{O}} \text{Products} \]

5. **Identify the Products**:
The products of this reaction are:
- A ketone (2-oxopropanal)
- An aldehyde (acetaldehyde)

6. **Count the Carbonyl Carbons**:
The carbonyl group (C=O) is present in both the ketone and the aldehyde. Therefore, we can count the carbonyl carbons:
- The ketone contributes 1 carbonyl carbon.
- The aldehyde contributes 1 carbonyl carbon.

7. **Total Number of Carbonyl Carbons**:
Adding these together, we find:
\[ \text{Total Carbonyl Carbons} = 1 (\text{from ketone}) + 1 (\text{from aldehyde}) = 2 \]

Thus, the number of carbonyl carbons in the product X is **2**.