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Two radioactive substance A and B have d...

Two radioactive substance `A` and `B` have decay constants `5 lambda` and `lambda` respectively. At `t=0` they have the same number of nuclei. The ratio of number of nuclei of nuclei of `A` to those of `B` will be `(1/e)^(2)` after a time interval

A

`(1)/(lambda)`

B

`(1)/(2lambda)`

C

`(2)/(lambda)`

D

`(1)/(4lambda)`

Text Solution

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The correct Answer is:
B
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Two radioactive substances A and B have decay constants 5lamda and lamda respectively. At t=0 they have the same number of nuclei of A to those of B will be (1/e)^2 after a time interval

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Knowledge Check

  • Two radioactive materials X_(1) and X_(2) have decay constants 5 lambda and lambda respectively. If initially they have the same number of nuclei, then the ratio of the number of muclei of X_(1) to that of X_(2) will be 1/e after a time

    A
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    B
    `1/2 lambda`
    C
    `1/ (4 lambda)`
    D
    `e/lambda`

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    A
    `1/(10lambda)`
    B
    `1/(11lambda)`
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  • Two radioactive materials X_1 and X_2 have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of X_1 to that of X_2 will be 1//e after a time.

    A
    `lamda`
    B
    `(1)/(2) lamda`
    C
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    D
    `( e)/(lamda)`

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