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U - tube moves with a constant speed pa...

U - tube moves with a constant speed parallel to the surface of a stationary liquid. The cross - section area of the lower part of the tube lowered into the liquid, is equal to `S_(1)` and that of the top part located over the liquid is `S_(2)`. Friction and formation of waves should be neglect difference in heights at both the openings of the tube.

The velocity of the liquid coming out of the top part as seen by an observer on the ground will be

A

`v((S_(1))/(S_(2)))`

B

`v(1+(S_(1))/(S_(2)))`

C

zero

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
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