A mixture of three alkyl chloride `CH_(3)Cl, CH_(3)CH_(2)Cl, CH_(3)CH_(2)CH_(2)Cl`
under goes Wurtz coupling reaction. The product contains ,

Options

A. Ethane, pentane, hexane only
B. Propane, pentane, butane only
C. Ethane, Propane, pentane, butane
D. Ethane, Propane, butane, pentane, hexane

Answer

To solve the problem, we will analyze the Wurtz coupling reaction involving the given alkyl chlorides: methyl chloride (CH₃Cl), ethyl chloride (CH₃CH₂Cl), and propyl chloride (CH₃CH₂CH₂Cl).

### Step-by-Step Solution:

1. **Identify the Alkyl Chlorides**:
We have three alkyl chlorides:
- Methyl chloride (CH₃Cl)
- Ethyl chloride (CH₃CH₂Cl)
- Propyl chloride (CH₃CH₂CH₂Cl)

2. **Understand the Wurtz Reaction**:
The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal (Na) to form alkanes. The general reaction can be summarized as:
\[ 2 R-X + 2 Na \rightarrow R-R + 2 NaX \]
where R is the alkyl group and X is the halide.

3. **Generate Radicals**:
When these alkyl chlorides react with sodium, they generate radicals:
- From CH₃Cl, we get CH₃• (methyl radical)
- From CH₃CH₂Cl, we get CH₃CH₂• (ethyl radical)
- From CH₃CH₂CH₂Cl, we get CH₃CH₂CH₂• (propyl radical)

4. **Self-Coupling Reactions**:
- CH₃• + CH₃• → C₂H₆ (Ethane)
- CH₃CH₂• + CH₃CH₂• → C₄H₁₀ (Butane)
- CH₃CH₂CH₂• + CH₃CH₂CH₂• → C₆H₁₄ (Hexane)

5. **Cross-Coupling Reactions**:
- CH₃• + CH₃CH₂• → C₃H₈ (Propane)
- CH₃• + CH₃CH₂CH₂• → C₄H₁₀ (Butane)
- CH₃CH₂• + CH₃CH₂CH₂• → C₅H₁₂ (Pentane)

6. **List All Possible Products**:
From the above reactions, we can summarize the products formed:
- Ethane (C₂H₆)
- Propane (C₃H₈)
- Butane (C₄H₁₀)
- Pentane (C₅H₁₂)
- Hexane (C₆H₁₄)

7. **Conclusion**:
The final products from the Wurtz coupling reaction of the given alkyl chlorides will contain:
- Ethane
- Propane
- Butane
- Pentane
- Hexane

Thus, the correct answer is that the product contains five alkanes: ethane, propane, butane, pentane, and hexane.