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A playground merry-go-round is at rest, ...

A playground merry-go-round is at rest, pivoted about a frictionless axis. A child of mass `m` runs along a path tangential to the rim with speed `v` and jumps on to the merry-go-round. If `R` is the radius of the merry-go-round and `I` is its moment of inertia, then the angular velocity of the merry-go-round is

A

`(mvR)/(mR^(2)+I)`

B

`(mvR)/(I)`

C

`(mR^(2)+I)/(mvR)`

D

`(I)/(mvR)`

Text Solution

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The correct Answer is:
A
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